Your percentages are correct if the mare is not homozygous for agouti, and the stallion does not have it. If he carries the agouti gene and she is hetero. it is 75% bay 25% black. If she is homo. for agouti you can not get black.
Posted From: 188.8.131.52
Posted on Sunday, June 19, 2005 - 08:11 am:
I definately agree, Black is not in the agouti at all. Only bay horses or horses bred from bays carry that gene. I think you are most likely to get a bay.
Your mare carries only a single copy of 'E'(she is 'Ee') which causes black hairs to be expressed. The stallion, being chestnut, does not express any black hairs, so is 'ee'. Therefore you have 50% chance of chestnut, and 50% chance of 'other'.
The mare, being bay, could either be heterozygous (1 copy) or homozygous (2 copies) for 'Agouti' - which restricts the black hairs to the points - ie gives you a bay. So she could be 'AA' or 'Aa'. She could NOT be 'aa' which is the absebce of Agouti, and presents itself as black.
The stallion is an unknown quantity - he could be anything (AA, Aa, or aa) as he doesn't express ANY black, we cannot tell what alleles he actually has.
If either parents is homozygous for Agouti (i.e. is 'AA') then you have 50% chestnut, 50% bay. If they are both hetrozygous for Agouti (ie are 'Aa') then you have a 50% chestnut, 37.5% bay, 12.5% black. If the stallion has no agouti and the mare is hetero, you have 50% chestnut, 25% bay, 25% black.
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